WEBVTT

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Hi, my name is Richard.

324500b4-60ad-4e49-819b-be1b9d780bb2-0
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We're looking at Tamura 2021, paper two,
question 13.

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Let's read it through.

582a9e54-3e40-4ec7-bff5-9bcf021bc037-0
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A region R in the XY plane is defined by
the simultaneous inequalities y -,

582a9e54-3e40-4ec7-bff5-9bcf021bc037-1
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X is less than 3 and y -,
X ^2 is less than one.

4d0e7b76-3d5b-4ddc-86f6-0f4e6405659c-0
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Which of the following statements is or
are true for every point in this region R?

faed0c8a-d98c-4e8a-b7e9-4dad66cd5987-0
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Statement 1 - 1 is less than X is less
than two.

c5e45cf6-4f2a-47ed-ab71-c00a9b73000d-0
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Statement 2 y -, X * y -,
X ^2 is less than three.

f424c6f3-04af-4244-b48c-754cb445e81b-0
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Statement 3 Y is less than five.

b0ba6753-e93a-464a-b36c-3e2dbd5fd034-0
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OK,
so I think the best approach to this is

b0ba6753-e93a-464a-b36c-3e2dbd5fd034-1
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to sketch the region R and then look at
it and try and decide which of these

b0ba6753-e93a-464a-b36c-3e2dbd5fd034-2
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three are true.

42573268-443c-43e5-bac5-86278fa7a972-0
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So we have these two simultaneous
inequalities.

f2120f6a-f6d8-43b7-91cc-31af52726ce4-0
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I think they're slightly easier for us to
work with if we rearrange them so the

f2120f6a-f6d8-43b7-91cc-31af52726ce4-1
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first one is the same as Y is less than X
+ 3.

04a573ee-e5e5-4d24-9d02-4c04062840d8-0
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If we want to imagine the set of points
which satisfy this whose X&amp;

04a573ee-e5e5-4d24-9d02-4c04062840d8-1
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Y coordinates satisfy this,
we might begin by thinking about the line

04a573ee-e5e5-4d24-9d02-4c04062840d8-2
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y = X + 3.

5f12a397-aa25-4944-a043-80033b22c449-0
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So the points on this line have their Y
coordinate equal to their X coordinate

5f12a397-aa25-4944-a043-80033b22c449-1
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plus three.

578b0f3b-0611-43a1-98a8-a4b41db2d018-0
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We want the Y coordinate to be less than
the X coordinate plus 3,

578b0f3b-0611-43a1-98a8-a4b41db2d018-1
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and that's the points which are below
this line.

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If you want to convince yourself about
that,

0aa610a2-b88f-4be1-9481-8691ebc6271c-1
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perhaps test the origin where Y is 0 and
X is 0, so 0 is certainly less than 0 + 3,

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so the origin satisfies this,
and from that,

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hopefully we can commit to ourselves.

3d725428-b90a-4243-9cac-d9242c61d73d-0
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It's the points below this line that we
need.

3eceafe9-973c-46fd-9918-751cd66389e7-0
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For the second inequality,
let's do the same thing.

0ca9d5c0-348a-4b54-b55d-d9cc04b32607-0
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Let's rearrange this into Y is less than
X ^2 + 1.

0475ff33-c489-4c0f-94e0-5de7ad6afb6e-0
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So again let's think about the set of
points where y = X ^2 + 1 first of all.

deca126f-711d-4600-b2ab-9c4e170ef431-0
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So that will just be the graph of y = X
^2 but moved up by 1 unit.

fbc7f2b5-5398-4ab7-a3fc-74d6dc413286-0
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So that will look something like this,
bearing in mind that that was 3,

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so this will be 1.

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And once again,
we want the point to below that curve.

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Again, just test, test.

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The origin X IS0Y is 0,
so 0 is less than 0 ^2 + 1.

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The origin satisfies it,
and it's all the points below that curve.

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Now for R,
we want both of these to be true,

0d66a3f4-5d07-4cd8-98f3-ba8ea7670e20-1
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so we need to be both below the line and
below the curve.

c89ae113-9f97-4d89-9379-392979a7f6b0-0
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And if we imagine what that looks like,
we would have this region here.

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Notice I'm carefully going to the curve
in this part and then back to the line

7ca564b7-f427-4ebc-8871-f84ec6e43ab9-1
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here.

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And one thing to notice about R,
I've only got a part of it here,

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but it would extend indefinitely up in
this direction and down in this direction

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and down to.

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So that's worth considering as we start
to think about 1-2 and three.

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Let's start by thinking about #1 So is it
true that every point in R has it's X

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coordinate between -1 and 2?

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So that would mean that they were all
sort of in this region.

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But we can imagine there are points with
X coordinates as big as we like off to

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the right here.

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So for example, if you want to pick one,
there might be this point here 70.

39ad4e5d-7ca6-4673-9555-ab9bb614a720-0
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So X is 7 and Y is 0.

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It's in the region because 0 -,
7 is less than 3 and 0 -,

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7 ^2 is less than one.

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But you can see that 7 is not between -1
and 2.

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So certainly 1 is not true for every
point in R Likewise for three,

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we can imagine that we if we if we look
in this direction,

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we can find points with Y coordinate
greater than or equal to 5 S 3 will not

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be true either for all points in R We can
just take a point up here whose Y

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coordinate is bigger than five and see
that's not true.

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Number 2 is a little bit more difficult
to think about.

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If we look at the relationship between
two and the two inequalities we have,

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we can see that the left hand side of two
is the product of these two left hand

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sides and the right hand side is the
product of the two right hand side.

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So it might be easy to think that this
follows from these two inequalities.

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However, if we stop and think for a while,
is it true that if we have a value less

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than three and a second value less than
one,

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then their product will be less than 3 *
1?

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If you think about extreme cases of that,
perhaps a very large negative value which

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is less than three,
and another very large negative value

dfc3ff1b-e427-4581-8973-196f7d227579-2
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which is less than one,
the product of those two would be a large

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positive value,
and it certainly wouldn't be less than 3.

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So we can see a kind of flaw in thinking
that this is true as a consequence of

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these two being true.

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So we need to interpret that in terms of
our diagram.

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I've already noticed that if this was a
large negative,

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if these were two large negative values,
then this would this bit of logic would

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not work.

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So what I'd like to get is these to be
large negative values.

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And if I take Y to be 0 and X to be a
large positive value.

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So for example,
coming back to my picture here further to

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the right, I might have a 10, 0.

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So if we look at this point, well, y -,
X is -10 Y is 0 and X is ten y -,

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X ^2 is -100 and the product of -10 and
-100 is +1000, which is not less than 3.

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So this point here is in our 10 zero.

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But it does not satisfy this.

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And we arrived at that point by thinking
about how the fact that this is true and

6622da36-b73f-4baa-b403-c3ee18a88edd-1
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this is true does not lead to this being
true.

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So it looks to me as though none of these
statements are true.

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And that means the answer we are looking
for is a here.

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One thing we might take away from this
question is that when we're working with

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inequalities and we're trying to decide
whether inequalities are a logical

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consequence of other inequalities,
it's sometimes useful to think about very

d4955cc1-a08d-42f7-853b-5022e2a2eb6f-3
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extreme cases of those inequalities.

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So in this case, we,
we imagined that this y -,

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X was a big negative value,
and this was also a very big negative

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value.

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And we could see that the product there
will be a large positive value.

d3965043-0ca2-42bb-bb22-07c53f2e2f0d-0
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It wouldn't be less than 3.

bf96652d-1f04-4b4d-b991-d2373a52fe57-0
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So and that lead us to this example point
here OF100,

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which was in our but for which 2 was not
true.